2x^2/3-4x=0

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Solution for 2x^2/3-4x=0 equation: 


x in (-oo:+oo)

(2*x^2)/3-(4*x) = 0

(2*x^2)/3-4*x = 0

2/3*x^2-4*x = 0

DELTA = (-4)^2-(0*2/3*4)

DELTA = 16

DELTA > 0

x = (16^(1/2)+4)/(2/3*2) or x = (4-16^(1/2))/(2/3*2)

x = 6 or x = 0

x in { 0, 6 }

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